Two Brackets, One Neat Product

Introduction to Trigonometry

Two Brackets, One Neat Product

CBSE Class 10 · Solve it one decision at a time. A wrong pick earns a nudge, never the answer.

Step 1 of 4

The problem

For 0∘<θ<90∘,0^\circ < \theta < 90^\circ, prove that (sec⁡θ−cos⁡θ)(cot⁡θ+tan⁡θ)=tan⁡θsec⁡θ.(\sec\theta - \cos\theta)(\cot\theta + \tan\theta) = \tan\theta\sec\theta.

Step 1 · Your move

Write sec⁡θ−cos⁡θ\sec\theta - \cos\theta as one fraction. What do you get?

(sec⁡θ−cos⁡θ)(cot⁡θ+tan⁡θ)(\sec\theta - \cos\theta)(\cot\theta + \tan\theta)
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