The Incircle Hypotenuse Split

CirclesVideo challenge · SAV21

The Incircle Hypotenuse Split

CBSE Class 10 · Solve it one decision at a time. A wrong pick earns a nudge, never the answer.

Step 1 of 8

The problem

In right △ABC\triangle ABC (with ∠B=90∘\angle B = 90^\circ), an incircle touches the hypotenuse ACAC at PP. Point PP divides ACAC into segments of lengths AP=6 cmAP = 6\text{ cm} and PC=4 cmPC = 4\text{ cm}. With ZERO side lengths and ZERO inradius given, find the exact area of △ABC\triangle ABC.

Step 1 · Your move

Before seeing the step-by-step breakdown, what area did you calculate for △ABC\triangle ABC?

ABCPOAP = 6 cmPC = 4 cm
Area of △ABC=?\triangle ABC = ?
Right △ABC (∠B = 90°) · the incircle with centre O touches AC at P (AP = 6 cm, PC = 4 cm)
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