The AP Sum Ratio to 11th Term Trap

Arithmetic ProgressionsVideo challenge · SAV28

The AP Sum Ratio to 11th Term Trap

CBSE Class 10 · Solve it one decision at a time. A wrong pick earns a nudge, never the answer.

Step 1 of 4

The problem

The ratio of the sums of nn terms of two arithmetic progressions is SnSn′=7n+14n+27\dfrac{S_n}{S'_n} = \dfrac{7n + 1}{4n + 27}. Find the ratio of their 11th11\text{th} terms, T11:T11′T_{11} : T'_{11}.

Step 1 · Your move

Before the guided steps, what ratio did you get for the 11th terms?

SnSn′=7n+14n+27\dfrac{S_n}{S'_n} = \dfrac{7n + 1}{4n + 27}
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